(X+3)^2=(x-3)+16(x-3)

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Solution for (X+3)^2=(x-3)+16(x-3) equation: 



(X+3)^2=(X-3)+16(X-3)

We move all terms to the left:

(X+3)^2-((X-3)+16(X-3))=0



We calculate terms in parentheses: -((X-3)+16(X-3)), so:

(X-3)+16(X-3)

We multiply parentheses

(X-3)+16X-48

We get rid of parentheses

X+16X-3-48

We add all the numbers together, and all the variables

17X-51

Back to the equation:

-(17X-51)



We get rid of parentheses

(X+3)^2-17X+51=0

We add all the numbers together, and all the variables

-17X+(X+3)^2+51=0

We move all terms containing X to the left, all other terms to the right

-17X+(X+3)^2=-51

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